The cholesterol lowering drug Lipitor has the molecular formula C33FH35N2O5 (all #s should be subscripted) ?

by Admin on August 12, 2010

What is its molecular mass?
What is the molecular mass in grams of one molecule of lipitor? If you take one pill that contains 15.0mg of lipitor, how many molecules have you ingested?

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Buck August 12, 2010 at 4:05 am

Just because there are a lot of atoms doesn’t change how you do the calculation of the molecular mass:

C33: 33 moles of carbon atoms x 12.01 g/mole = 396.3 g of C
F(1): 1 mole of F atoms x 19.00 g / mole = 19.0 g of F
H35: 35 moles of H atoms x 1.008 g/mole = 35.8 g of H
N2: 2 moles of N atoms x 14.01 g/mole = 28.0 g of N
O5: 5 moles of O atoms x 16.00 g/mole = 80.0 moles of O

396.3 + 19.0 + 35.8 + 28.0 + 80.0 = 559.1 g / mole of Lipitor

If 6.023 x 10^23 molecules of Lipitor (1 mole) has a mass of 559.1 g, then 559.1 g Lipitor/mole Lipitor / 6.023 x 10^23 molecules of Lipitor / mole Lipitor = 559.1 / 6.023 x 10^23 = ? g/molecule of Lipitor

15.0 mg = 0.015 g of Lipitor. 0.015 / 559.1 = ? moles of Lipitor in 15 mg.

? moles of Lipitor / 6.023 x 10^23 molecules / mole = ? moleucles of Lipitor.

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